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130012113120 = 253517109146173
BaseRepresentation
bin111100100010101010…
…0110110100011100000
3110102120202201122200220
41321011110312203200
54112231100104440
6135420550443040
712251551504401
oct1710524664340
9412522648626
10130012113120
11501574a297a
1221244963480
13c34c556166
146414d3d9a8
1535ade578d0
hex1e455368e0

130012113120 has 192 divisors, whose sum is σ = 437609874240. Its totient is φ = 32330907648.

The previous prime is 130012113097. The next prime is 130012113221. The reversal of 130012113120 is 21311210031.

It is a happy number.

It is a super-2 number, since 2×1300121131202 (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 130012113120.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 816354 + ... + 962526.

It is an arithmetic number, because the mean of its divisors is an integer number (2279218095).

Almost surely, 2130012113120 is an apocalyptic number.

130012113120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130012113120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (218804937120).

130012113120 is an abundant number, since it is smaller than the sum of its proper divisors (307597761120).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130012113120 is a wasteful number, since it uses less digits than its factorization.

130012113120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 146317 (or 146309 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 130012113120 its reverse (21311210031), we get a palindrome (151323323151).

The spelling of 130012113120 in words is "one hundred thirty billion, twelve million, one hundred thirteen thousand, one hundred twenty".