Base | Representation |
---|---|
bin | 111100100010101010… |
… | …1001100000011111011 |
3 | 110102120202220010112112 |
4 | 1321011111030003323 |
5 | 4112231110414321 |
6 | 135420552402535 |
7 | 12251552322254 |
oct | 1710525140373 |
9 | 412522803475 |
10 | 130012201211 |
11 | 50157553082 |
12 | 212449a644b |
13 | c34c587299 |
14 | 6414d63b2b |
15 | 35ade73a5b |
hex | 1e4554c0fb |
130012201211 has 2 divisors, whose sum is σ = 130012201212. Its totient is φ = 130012201210.
The previous prime is 130012201201. The next prime is 130012201247. The reversal of 130012201211 is 112102210031.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130012201211 is a prime.
It is a super-3 number, since 3×1300122012113 (a number of 34 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (130012201201) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65006100605 + 65006100606.
It is an arithmetic number, because the mean of its divisors is an integer number (65006100606).
Almost surely, 2130012201211 is an apocalyptic number.
130012201211 is a deficient number, since it is larger than the sum of its proper divisors (1).
130012201211 is an equidigital number, since it uses as much as digits as its factorization.
130012201211 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 130012201211 its reverse (112102210031), we get a palindrome (242114411242).
The spelling of 130012201211 in words is "one hundred thirty billion, twelve million, two hundred one thousand, two hundred eleven".
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