Base | Representation |
---|---|
bin | 11101100011111011010101… |
… | …011101110001000110100111 |
3 | 122001100001022122100211222120 |
4 | 131203323111131301012213 |
5 | 114020110032244301411 |
6 | 1140302444341401023 |
7 | 36246034353662121 |
oct | 3543732535610647 |
9 | 561301278324876 |
10 | 130012241400231 |
11 | 38475977949423 |
12 | 126b92b0709173 |
13 | 577114273ac88 |
14 | 24168a9c98211 |
15 | 1006db4100106 |
hex | 763ed57711a7 |
130012241400231 has 32 divisors (see below), whose sum is σ = 180674919195840. Its totient is φ = 83059469746176.
The previous prime is 130012241400137. The next prime is 130012241400233. The reversal of 130012241400231 is 132004142210031.
It is not a de Polignac number, because 130012241400231 - 27 = 130012241400103 is a prime.
It is a super-2 number, since 2×1300122414002312 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130012241400233) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 4302516 + ... + 16689401.
It is an arithmetic number, because the mean of its divisors is an integer number (5646091224870).
Almost surely, 2130012241400231 is an apocalyptic number.
130012241400231 is a deficient number, since it is larger than the sum of its proper divisors (50662677795609).
130012241400231 is a wasteful number, since it uses less digits than its factorization.
130012241400231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20992483.
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 130012241400231 its reverse (132004142210031), we get a palindrome (262016383610262).
The spelling of 130012241400231 in words is "one hundred thirty trillion, twelve billion, two hundred forty-one million, four hundred thousand, two hundred thirty-one".
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