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1300123102307 is a prime number
BaseRepresentation
bin10010111010110101011…
…000000010110001100011
311121021211210222200211212
4102322311120002301203
5132300123003233212
62433133542100335
7162634156013261
oct22726530026143
94537753880755
101300123102307
11461419662837
1218bb8071a6ab
13957a7769443
1446cd7a71431
1523c44b3ee22
hex12eb5602c63

1300123102307 has 2 divisors, whose sum is σ = 1300123102308. Its totient is φ = 1300123102306.

The previous prime is 1300123102301. The next prime is 1300123102309. The reversal of 1300123102307 is 7032013210031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1300123102307 - 210 = 1300123101283 is a prime.

Together with 1300123102309, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1300123102301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650061551153 + 650061551154.

It is an arithmetic number, because the mean of its divisors is an integer number (650061551154).

Almost surely, 21300123102307 is an apocalyptic number.

1300123102307 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300123102307 is an equidigital number, since it uses as much as digits as its factorization.

1300123102307 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 756, while the sum is 23.

Adding to 1300123102307 its reverse (7032013210031), we get a palindrome (8332136312338).

The spelling of 1300123102307 in words is "one trillion, three hundred billion, one hundred twenty-three million, one hundred two thousand, three hundred seven".