Base | Representation |
---|---|
bin | 10010111010110101110… |
… | …010110111000010101001 |
3 | 11121021212022012211221221 |
4 | 102322311302313002221 |
5 | 132300131303212022 |
6 | 2433134352502041 |
7 | 162634302532354 |
oct | 22726562670251 |
9 | 4537768184857 |
10 | 1300130132137 |
11 | 461422624411 |
12 | 18bb82b4a921 |
13 | 957a905b0c5 |
14 | 46cd898129b |
15 | 23c4557ccc7 |
hex | 12eb5cb70a9 |
1300130132137 has 2 divisors, whose sum is σ = 1300130132138. Its totient is φ = 1300130132136.
The previous prime is 1300130132113. The next prime is 1300130132143. The reversal of 1300130132137 is 7312310310031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1299271700736 + 858431401 = 1139856^2 + 29299^2 .
It is a cyclic number.
It is not a de Polignac number, because 1300130132137 - 215 = 1300130099369 is a prime.
It is not a weakly prime, because it can be changed into another prime (1300130132437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650065066068 + 650065066069.
It is an arithmetic number, because the mean of its divisors is an integer number (650065066069).
Almost surely, 21300130132137 is an apocalyptic number.
It is an amenable number.
1300130132137 is a deficient number, since it is larger than the sum of its proper divisors (1).
1300130132137 is an equidigital number, since it uses as much as digits as its factorization.
1300130132137 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1134, while the sum is 25.
Adding to 1300130132137 its reverse (7312310310031), we get a palindrome (8612440442168).
The spelling of 1300130132137 in words is "one trillion, three hundred billion, one hundred thirty million, one hundred thirty-two thousand, one hundred thirty-seven".
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