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130013043427 is a prime number
BaseRepresentation
bin111100100010101100…
…0011001101011100011
3110102120211110220211201
41321011120121223203
54112231314342202
6135421022422031
712251562430561
oct1710530315343
9412524426751
10130013043427
1150157a78923
1221245131917
13c34c7c0737
146415102a31
1535ae08d387
hex1e45619ae3

130013043427 has 2 divisors, whose sum is σ = 130013043428. Its totient is φ = 130013043426.

The previous prime is 130013043409. The next prime is 130013043451. The reversal of 130013043427 is 724340310031.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 130013043427 - 219 = 130012519139 is a prime.

It is a super-2 number, since 2×1300130434272 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130013043395 and 130013043404.

It is not a weakly prime, because it can be changed into another prime (130013040427) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65006521713 + 65006521714.

It is an arithmetic number, because the mean of its divisors is an integer number (65006521714).

Almost surely, 2130013043427 is an apocalyptic number.

130013043427 is a deficient number, since it is larger than the sum of its proper divisors (1).

130013043427 is an equidigital number, since it uses as much as digits as its factorization.

130013043427 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 28.

Adding to 130013043427 its reverse (724340310031), we get a palindrome (854353353458).

The spelling of 130013043427 in words is "one hundred thirty billion, thirteen million, forty-three thousand, four hundred twenty-seven".