130013043451 has 2 divisors, whose sum is σ = 130013043452. Its totient is φ = 130013043450.

The previous prime is 130013043427. The next prime is 130013043463. The reversal of 130013043451 is 154340310031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130013043451 - 2⁷ = 130013043323 is a prime.

It is a super-2 number, since 2×130013043451² (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (130013049451) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65006521725 + 65006521726.

It is an arithmetic number, because the mean of its divisors is an integer number (65006521726).

Almost surely, 2^130013043451 is an apocalyptic number.

130013043451 is a deficient number, since it is larger than the sum of its proper divisors (1).

130013043451 is an equidigital number, since it uses as much as digits as its factorization.

130013043451 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 130013043451 its reverse (154340310031), we get a palindrome (284353353482).

The spelling of 130013043451 in words is "one hundred thirty billion, thirteen million, forty-three thousand, four hundred fifty-one".