130013043441 has 4 divisors (see below), whose sum is σ = 173350724592. Its totient is φ = 86675362292.

The previous prime is 130013043427. The next prime is 130013043451. The reversal of 130013043441 is 144340310031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 130013043441 - 2⁵ = 130013043409 is a prime.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (130013043451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21668840571 + ... + 21668840576.

It is an arithmetic number, because the mean of its divisors is an integer number (43337681148).

Almost surely, 2^130013043441 is an apocalyptic number.

It is an amenable number.

130013043441 is a deficient number, since it is larger than the sum of its proper divisors (43337681151).

130013043441 is an equidigital number, since it uses as much as digits as its factorization.

130013043441 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 43337681150.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 130013043441 its reverse (144340310031), we get a palindrome (274353353472).

The spelling of 130013043441 in words is "one hundred thirty billion, thirteen million, forty-three thousand, four hundred forty-one".