Base | Representation |
---|---|
bin | 111100100010101100… |
… | …0101100011000001011 |
3 | 110102120211121210220011 |
4 | 1321011120230120023 |
5 | 4112231324320021 |
6 | 135421024212351 |
7 | 12251563200055 |
oct | 1710530543013 |
9 | 412524553804 |
10 | 130013120011 |
11 | 50158020415 |
12 | 2124516a0b7 |
13 | c34c819558 |
14 | 64151228d5 |
15 | 35ae0a5de1 |
hex | 1e4562c60b |
130013120011 has 2 divisors, whose sum is σ = 130013120012. Its totient is φ = 130013120010.
The previous prime is 130013120009. The next prime is 130013120053. The reversal of 130013120011 is 110021310031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130013120011 - 21 = 130013120009 is a prime.
It is a super-2 number, since 2×1300131200112 (a number of 23 digits) contains 22 as substring.
Together with 130013120009, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 130013119973 and 130013120000.
It is not a weakly prime, because it can be changed into another prime (130013120411) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65006560005 + 65006560006.
It is an arithmetic number, because the mean of its divisors is an integer number (65006560006).
Almost surely, 2130013120011 is an apocalyptic number.
130013120011 is a deficient number, since it is larger than the sum of its proper divisors (1).
130013120011 is an equidigital number, since it uses as much as digits as its factorization.
130013120011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 130013120011 its reverse (110021310031), we get a palindrome (240034430042).
The spelling of 130013120011 in words is "one hundred thirty billion, thirteen million, one hundred twenty thousand, eleven".
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