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13001343243004 = 2219171070305829
BaseRepresentation
bin1011110100110001110001…
…1100100001001011111100
31201000220201222001100021101
42331030130130201023330
53201003222332234004
643352422402542444
72511213256104634
oct275143434411374
951026658040241
1013001343243004
114162925353086
12155b8b7667a24
1373403805406c
1432d3a85a16c4
151782dc569ba4
hexbd31c7212fc

13001343243004 has 12 divisors (see below), whose sum is σ = 23949842816200. Its totient is φ = 6158531009808.

The previous prime is 13001343242989. The next prime is 13001343243019. The reversal of 13001343243004 is 40034234310031.

It is an interprime number because it is at equal distance from previous prime (13001343242989) and next prime (13001343243019).

It is a super-2 number, since 2×130013432430042 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 85535152839 + ... + 85535152990.

Almost surely, 213001343243004 is an apocalyptic number.

It is an amenable number.

13001343243004 is a deficient number, since it is larger than the sum of its proper divisors (10948499573196).

13001343243004 is a wasteful number, since it uses less digits than its factorization.

13001343243004 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 171070305852 (or 171070305850 counting only the distinct ones).

The product of its (nonzero) digits is 10368, while the sum is 28.

Adding to 13001343243004 its reverse (40034234310031), we get a palindrome (53035577553035).

The spelling of 13001343243004 in words is "thirteen trillion, one billion, three hundred forty-three million, two hundred forty-three thousand, four".

Divisors: 1 2 4 19 38 76 171070305829 342140611658 684281223316 3250335810751 6500671621502 13001343243004