130014111737 has 2 divisors, whose sum is σ = 130014111738. Its totient is φ = 130014111736.

The previous prime is 130014111727. The next prime is 130014111739. The reversal of 130014111737 is 737111410031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110093894416 + 19920217321 = 331804^2 + 141139^2 .

It is a cyclic number.

It is not a de Polignac number, because 130014111737 - 2⁶ = 130014111673 is a prime.

It is a super-2 number, since 2×130014111737² (a number of 23 digits) contains 22 as substring.

Together with 130014111739, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (130014111739) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65007055868 + 65007055869.

It is an arithmetic number, because the mean of its divisors is an integer number (65007055869).

Almost surely, 2^130014111737 is an apocalyptic number.

It is an amenable number.

130014111737 is a deficient number, since it is larger than the sum of its proper divisors (1).

130014111737 is an equidigital number, since it uses as much as digits as its factorization.

130014111737 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1764, while the sum is 29.

Adding to 130014111737 its reverse (737111410031), we get a palindrome (867125521768).

The spelling of 130014111737 in words is "one hundred thirty billion, fourteen million, one hundred eleven thousand, seven hundred thirty-seven".