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130014111743 = 1258310332521
BaseRepresentation
bin111100100010101110…
…0011110011111111111
3110102120220111012021222
41321011130132133333
54112232103033433
6135421101343555
712251604500315
oct1710534363777
9412526435258
10130014111743
115015863852a
1221245567bbb
13c34caa5a89
1464153000b5
1535ae1eeb98
hex1e4571e7ff

130014111743 has 4 divisors (see below), whose sum is σ = 130024456848. Its totient is φ = 130003766640.

The previous prime is 130014111739. The next prime is 130014111751. The reversal of 130014111743 is 347111410031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 347111410031 = 479117244921.

It is a cyclic number.

It is not a de Polignac number, because 130014111743 - 22 = 130014111739 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130014111443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5153678 + ... + 5178843.

It is an arithmetic number, because the mean of its divisors is an integer number (32506114212).

Almost surely, 2130014111743 is an apocalyptic number.

130014111743 is a deficient number, since it is larger than the sum of its proper divisors (10345105).

130014111743 is a wasteful number, since it uses less digits than its factorization.

130014111743 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10345104.

The product of its (nonzero) digits is 1008, while the sum is 26.

Adding to 130014111743 its reverse (347111410031), we get a palindrome (477125521774).

The spelling of 130014111743 in words is "one hundred thirty billion, fourteen million, one hundred eleven thousand, seven hundred forty-three".

Divisors: 1 12583 10332521 130014111743