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130014111751 is a prime number
BaseRepresentation
bin111100100010101110…
…0011110100000000111
3110102120220111012022021
41321011130132200013
54112232103034001
6135421101344011
712251604500326
oct1710534364007
9412526435267
10130014111751
1150158638537
1221245568007
13c34caa5a94
1464153000bd
1535ae1eeba1
hex1e4571e807

130014111751 has 2 divisors, whose sum is σ = 130014111752. Its totient is φ = 130014111750.

The previous prime is 130014111739. The next prime is 130014111769. The reversal of 130014111751 is 157111410031.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 130014111751 - 29 = 130014111239 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130014171751) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65007055875 + 65007055876.

It is an arithmetic number, because the mean of its divisors is an integer number (65007055876).

Almost surely, 2130014111751 is an apocalyptic number.

130014111751 is a deficient number, since it is larger than the sum of its proper divisors (1).

130014111751 is an equidigital number, since it uses as much as digits as its factorization.

130014111751 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 420, while the sum is 25.

Adding to 130014111751 its reverse (157111410031), we get a palindrome (287125521782).

The spelling of 130014111751 in words is "one hundred thirty billion, fourteen million, one hundred eleven thousand, seven hundred fifty-one".