Base | Representation |
---|---|
bin | 111100100010101110… |
… | …0101101001001100111 |
3 | 110102120220121020121111 |
4 | 1321011130231021213 |
5 | 4112232111444001 |
6 | 135421102525451 |
7 | 12251605140262 |
oct | 1710534551147 |
9 | 412526536544 |
10 | 130014171751 |
11 | 50158679622 |
12 | 21245596887 |
13 | c34cac7199 |
14 | 6415317cd9 |
15 | 35ae212851 |
hex | 1e4572d267 |
130014171751 has 2 divisors, whose sum is σ = 130014171752. Its totient is φ = 130014171750.
The previous prime is 130014171743. The next prime is 130014171773. The reversal of 130014171751 is 157171410031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130014171751 - 23 = 130014171743 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130014174751) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65007085875 + 65007085876.
It is an arithmetic number, because the mean of its divisors is an integer number (65007085876).
Almost surely, 2130014171751 is an apocalyptic number.
130014171751 is a deficient number, since it is larger than the sum of its proper divisors (1).
130014171751 is an equidigital number, since it uses as much as digits as its factorization.
130014171751 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2940, while the sum is 31.
Adding to 130014171751 its reverse (157171410031), we get a palindrome (287185581782).
The spelling of 130014171751 in words is "one hundred thirty billion, fourteen million, one hundred seventy-one thousand, seven hundred fifty-one".
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