Base | Representation |
---|---|
bin | 11101100011111101010001… |
… | …100111001000101111010011 |
3 | 122001100020200210120121211110 |
4 | 131203331101213020233103 |
5 | 114020123314000343443 |
6 | 1140303431143544403 |
7 | 36246140104520313 |
oct | 3543752147105723 |
9 | 561306623517743 |
10 | 130014324231123 |
11 | 38476846620072 |
12 | 126b979215b103 |
13 | 57713b50c70a7 |
14 | 2416a26755443 |
15 | 1006e86dc5233 |
hex | 763f519c8bd3 |
130014324231123 has 32 divisors (see below), whose sum is σ = 184393888943616. Its totient is φ = 81303055561728.
The previous prime is 130014324231013. The next prime is 130014324231161. The reversal of 130014324231123 is 321132423410031.
It is not a de Polignac number, because 130014324231123 - 238 = 129739446324179 is a prime.
It is a super-2 number, since 2×1300143242311232 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (130014324231173) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1436965 + ... + 16189302.
It is an arithmetic number, because the mean of its divisors is an integer number (5762309029488).
Almost surely, 2130014324231123 is an apocalyptic number.
130014324231123 is a deficient number, since it is larger than the sum of its proper divisors (54379564712493).
130014324231123 is a wasteful number, since it uses less digits than its factorization.
130014324231123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17628363.
The product of its (nonzero) digits is 10368, while the sum is 30.
Adding to 130014324231123 its reverse (321132423410031), we get a palindrome (451146747641154).
The spelling of 130014324231123 in words is "one hundred thirty trillion, fourteen billion, three hundred twenty-four million, two hundred thirty-one thousand, one hundred twenty-three".
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