130014433 has 2 divisors, whose sum is σ = 130014434. Its totient is φ = 130014432.

The previous prime is 130014431. The next prime is 130014449. The reversal of 130014433 is 334410031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 98743969 + 31270464 = 9937^2 + 5592^2 .

It is an emirp because it is prime and its reverse (334410031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130014433 - 2¹ = 130014431 is a prime.

It is a super-2 number, since 2×130014433² = 33807505576622978, which contains 22 as substring.

Together with 130014431, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 130014433.

It is not a weakly prime, because it can be changed into another prime (130014431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65007216 + 65007217.

It is an arithmetic number, because the mean of its divisors is an integer number (65007217).

Almost surely, 2^130014433 is an apocalyptic number.

It is an amenable number.

130014433 is a deficient number, since it is larger than the sum of its proper divisors (1).

130014433 is an equidigital number, since it uses as much as digits as its factorization.

130014433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 19.

The square root of 130014433 is about 11402.3871623446. The cubic root of 130014433 is about 506.5984485621.

Adding to 130014433 its reverse (334410031), we get a palindrome (464424464).

The spelling of 130014433 in words is "one hundred thirty million, fourteen thousand, four hundred thirty-three".