Base | Representation |
---|---|
bin | 100110101111110… |
… | …1011011100100011 |
3 | 10100121110110120121 |
4 | 1031133223130203 |
5 | 10130314300201 |
6 | 333002421111 |
7 | 44135043634 |
oct | 11537533443 |
9 | 3317413517 |
10 | 1300150051 |
11 | 60799aa82 |
12 | 303501797 |
13 | 17948b375 |
14 | c495d88b |
15 | 7921e9a1 |
hex | 4d7eb723 |
1300150051 has 2 divisors, whose sum is σ = 1300150052. Its totient is φ = 1300150050.
The previous prime is 1300150039. The next prime is 1300150063. The reversal of 1300150051 is 1500510031.
It is a balanced prime because it is at equal distance from previous prime (1300150039) and next prime (1300150063).
It is a cyclic number.
It is not a de Polignac number, because 1300150051 - 213 = 1300141859 is a prime.
It is not a weakly prime, because it can be changed into another prime (1300150001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650075025 + 650075026.
It is an arithmetic number, because the mean of its divisors is an integer number (650075026).
Almost surely, 21300150051 is an apocalyptic number.
1300150051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1300150051 is an equidigital number, since it uses as much as digits as its factorization.
1300150051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 75, while the sum is 16.
The square root of 1300150051 is about 36057.5935275775. The cubic root of 1300150051 is about 1091.4348723670.
Adding to 1300150051 its reverse (1500510031), we get a palindrome (2800660082).
The spelling of 1300150051 in words is "one billion, three hundred million, one hundred fifty thousand, fifty-one".
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