Base | Representation |
---|---|
bin | 1111011111111… |
… | …01111110000111 |
3 | 100001122110012111 |
4 | 13233331332013 |
5 | 231240440421 |
6 | 20522401451 |
7 | 3136052542 |
oct | 757757607 |
9 | 301573174 |
10 | 130015111 |
11 | 67432306 |
12 | 37660287 |
13 | 20c22625 |
14 | 133a5859 |
15 | b632ee1 |
hex | 7bfdf87 |
130015111 has 2 divisors, whose sum is σ = 130015112. Its totient is φ = 130015110.
The previous prime is 130015103. The next prime is 130015121. The reversal of 130015111 is 111510031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130015111 - 23 = 130015103 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130015091 and 130015100.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130015121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65007555 + 65007556.
It is an arithmetic number, because the mean of its divisors is an integer number (65007556).
Almost surely, 2130015111 is an apocalyptic number.
130015111 is a deficient number, since it is larger than the sum of its proper divisors (1).
130015111 is an equidigital number, since it uses as much as digits as its factorization.
130015111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15, while the sum is 13.
The square root of 130015111 is about 11402.4168929223. The cubic root of 130015111 is about 506.5993291647.
Adding to 130015111 its reverse (111510031), we get a palindrome (241525142).
The spelling of 130015111 in words is "one hundred thirty million, fifteen thousand, one hundred eleven".
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