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130015334131 is a prime number
BaseRepresentation
bin111100100010110000…
…1001000111011110011
3110102120222210022002121
41321011201020323303
54112232411143011
6135421143455111
712251621051164
oct1710541107363
9412528708077
10130015334131
11501592a2971
1221245a57497
13c350113297
14641553b76b
1535ae391e71
hex1e45848ef3

130015334131 has 2 divisors, whose sum is σ = 130015334132. Its totient is φ = 130015334130.

The previous prime is 130015334123. The next prime is 130015334159. The reversal of 130015334131 is 131433510031.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 130015334131 - 23 = 130015334123 is a prime.

It is a super-3 number, since 3×1300153341313 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 130015334096 and 130015334105.

It is not a weakly prime, because it can be changed into another prime (130015334531) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65007667065 + 65007667066.

It is an arithmetic number, because the mean of its divisors is an integer number (65007667066).

Almost surely, 2130015334131 is an apocalyptic number.

130015334131 is a deficient number, since it is larger than the sum of its proper divisors (1).

130015334131 is an equidigital number, since it uses as much as digits as its factorization.

130015334131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1620, while the sum is 25.

Adding to 130015334131 its reverse (131433510031), we get a palindrome (261448844162).

The spelling of 130015334131 in words is "one hundred thirty billion, fifteen million, three hundred thirty-four thousand, one hundred thirty-one".