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13001608354488 = 23313192773149333
BaseRepresentation
bin1011110100110010110000…
…1111110101101010111000
31201000221102102220101212020
42331030230033311222320
53201004243214320423
643352504553114440
72511222655365465
oct275145417655270
951027372811766
1013001608354488
114162a50a68286
12155b9703b8a20
1373407ac57a70
1432d3d189266c
151783059864e3
hexbd32c3f5ab8

13001608354488 has 192 divisors, whose sum is σ = 36991668500640. Its totient is φ = 3785014268928.

The previous prime is 13001608354433. The next prime is 13001608354529. The reversal of 13001608354488 is 88445380610031.

It is a self number, because there is not a number n which added to its sum of digits gives 13001608354488.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 86989870 + ... + 87139202.

Almost surely, 213001608354488 is an apocalyptic number.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13001608354488, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18495834250320).

13001608354488 is an abundant number, since it is smaller than the sum of its proper divisors (23990060146152).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13001608354488 is a wasteful number, since it uses less digits than its factorization.

13001608354488 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 150166 (or 150143 counting only the distinct ones).

The product of its (nonzero) digits is 2211840, while the sum is 51.

The spelling of 13001608354488 in words is "thirteen trillion, one billion, six hundred eight million, three hundred fifty-four thousand, four hundred eighty-eight".