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1300166390183 is a prime number
BaseRepresentation
bin10010111010110111111…
…101001011000110100111
311121021221211102221122112
4102322313331023012213
5132300220043441213
62433142125551235
7162635222654063
oct22726775130647
94537854387575
101300166390183
11461441039641
1218bb9311551b
13957b371467b
1446cdd6dcaa3
1523c48840ea8
hex12eb7f4b1a7

1300166390183 has 2 divisors, whose sum is σ = 1300166390184. Its totient is φ = 1300166390182.

The previous prime is 1300166390177. The next prime is 1300166390191. The reversal of 1300166390183 is 3810936610031.

It is a weak prime.

It is an emirp because it is prime and its reverse (3810936610031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1300166390183 - 28 = 1300166389927 is a prime.

It is a super-2 number, since 2×13001663901832 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1300166390183.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1300166390483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650083195091 + 650083195092.

It is an arithmetic number, because the mean of its divisors is an integer number (650083195092).

Almost surely, 21300166390183 is an apocalyptic number.

1300166390183 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300166390183 is an equidigital number, since it uses as much as digits as its factorization.

1300166390183 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69984, while the sum is 41.

The spelling of 1300166390183 in words is "one trillion, three hundred billion, one hundred sixty-six million, three hundred ninety thousand, one hundred eighty-three".