Base | Representation |
---|---|
bin | 111100100010111001… |
… | …1010111011011100110 |
3 | 110102121022210001020111 |
4 | 1321011303113123212 |
5 | 4112240122041402 |
6 | 135421434123234 |
7 | 12252006501136 |
oct | 1710563273346 |
9 | 412538701214 |
10 | 130020112102 |
11 | 50160a66701 |
12 | 2124758051a |
13 | c3510c6c9a |
14 | 6416022ac6 |
15 | 35ae9d79d7 |
hex | 1e45cd76e6 |
130020112102 has 4 divisors (see below), whose sum is σ = 195030168156. Its totient is φ = 65010056050.
The previous prime is 130020112051. The next prime is 130020112109. The reversal of 130020112102 is 201211020031.
It is a semiprime because it is the product of two primes.
It is a super-4 number, since 4×1300201121024 (a number of 46 digits) contains 4444 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130020112109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32505028024 + ... + 32505028027.
It is an arithmetic number, because the mean of its divisors is an integer number (48757542039).
Almost surely, 2130020112102 is an apocalyptic number.
130020112102 is a deficient number, since it is larger than the sum of its proper divisors (65010056054).
130020112102 is an equidigital number, since it uses as much as digits as its factorization.
130020112102 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 65010056053.
The product of its (nonzero) digits is 24, while the sum is 13.
Adding to 130020112102 its reverse (201211020031), we get a palindrome (331231132133).
The spelling of 130020112102 in words is "one hundred thirty billion, twenty million, one hundred twelve thousand, one hundred two".
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