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130020210132 = 22310835017511
BaseRepresentation
bin111100100010111001…
…1101111010111010100
3110102121022222000201020
41321011303233113110
54112240133211012
6135421440201140
712252010360011
oct1710563572724
9412538860636
10130020210132
115016102331a
12212476091b0
13c35112c7a7
14641604a708
1535aea06a8c
hex1e45cef5d4

130020210132 has 12 divisors (see below), whose sum is σ = 303380490336. Its totient is φ = 43340070040.

The previous prime is 130020210119. The next prime is 130020210143. The reversal of 130020210132 is 231012020031.

It is a tau number, because it is divible by the number of its divisors (12).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5417508744 + ... + 5417508767.

It is an arithmetic number, because the mean of its divisors is an integer number (25281707528).

Almost surely, 2130020210132 is an apocalyptic number.

130020210132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

130020210132 is an abundant number, since it is smaller than the sum of its proper divisors (173360280204).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130020210132 is a wasteful number, since it uses less digits than its factorization.

130020210132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10835017518 (or 10835017516 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 130020210132 its reverse (231012020031), we get a palindrome (361032230163).

The spelling of 130020210132 in words is "one hundred thirty billion, twenty million, two hundred ten thousand, one hundred thirty-two".

Divisors: 1 2 3 4 6 12 10835017511 21670035022 32505052533 43340070044 65010105066 130020210132