Search a number
-
+
130020212120130 = 23252333619232329
BaseRepresentation
bin11101100100000010110000…
…100011101001101001000010
3122001100210220010200101010200
4131210002300203221221002
5114020222343300321010
61140310243313510030
736246436030662423
oct3544026043515102
9561323803611120
10130020212120130
1138479298138242
12126ba955b72316
135771b12b9b997
1424170246dd64a
1510071cdc64cc0
hex7640b08e9a42

130020212120130 has 48 divisors (see below), whose sum is σ = 338197452423480. Its totient is φ = 34657194933504.

The previous prime is 130020212120093. The next prime is 130020212120251. The reversal of 130020212120130 is 31021212020031.

130020212120130 is a `hidden beast` number, since 1 + 300 + 2 + 0 + 21 + 212 + 0 + 130 = 666.

It can be written as a sum of positive squares in 4 ways, for example, as 69293088117009 + 60727124003121 = 8324247^2 + 7792761^2 .

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 309406195 + ... + 309826134.

Almost surely, 2130020212120130 is an apocalyptic number.

130020212120130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

130020212120130 is an abundant number, since it is smaller than the sum of its proper divisors (208177240303350).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130020212120130 is a wasteful number, since it uses less digits than its factorization.

130020212120130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 619234675 (or 619234672 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 130020212120130 its reverse (31021212020031), we get a palindrome (161041424140161).

It can be divided in two parts, 13002021 and 2120130, that added together give a palindrome (15122151).

The spelling of 130020212120130 in words is "one hundred thirty trillion, twenty billion, two hundred twelve million, one hundred twenty thousand, one hundred thirty".

Divisors: 1 2 3 5 6 9 10 15 18 30 45 90 2333 4666 6999 11665 13998 20997 23330 34995 41994 69990 104985 209970 619232329 1238464658 1857696987 3096161645 3715393974 5573090961 6192323290 9288484935 11146181922 18576969870 27865454805 55730909610 1444669023557 2889338047114 4334007070671 7223345117785 8668014141342 13002021212013 14446690235570 21670035353355 26004042424026 43340070706710 65010106060065 130020212120130