Base | Representation |
---|---|
bin | 11101100100000010110000… |
… | …100011101001101001000010 |
3 | 122001100210220010200101010200 |
4 | 131210002300203221221002 |
5 | 114020222343300321010 |
6 | 1140310243313510030 |
7 | 36246436030662423 |
oct | 3544026043515102 |
9 | 561323803611120 |
10 | 130020212120130 |
11 | 38479298138242 |
12 | 126ba955b72316 |
13 | 5771b12b9b997 |
14 | 24170246dd64a |
15 | 10071cdc64cc0 |
hex | 7640b08e9a42 |
130020212120130 has 48 divisors (see below), whose sum is σ = 338197452423480. Its totient is φ = 34657194933504.
The previous prime is 130020212120093. The next prime is 130020212120251. The reversal of 130020212120130 is 31021212020031.
130020212120130 is a `hidden beast` number, since 1 + 300 + 2 + 0 + 21 + 212 + 0 + 130 = 666.
It can be written as a sum of positive squares in 4 ways, for example, as 69293088117009 + 60727124003121 = 8324247^2 + 7792761^2 .
It is a Harshad number since it is a multiple of its sum of digits (18).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 309406195 + ... + 309826134.
Almost surely, 2130020212120130 is an apocalyptic number.
130020212120130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
130020212120130 is an abundant number, since it is smaller than the sum of its proper divisors (208177240303350).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130020212120130 is a wasteful number, since it uses less digits than its factorization.
130020212120130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 619234675 (or 619234672 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 18.
Adding to 130020212120130 its reverse (31021212020031), we get a palindrome (161041424140161).
It can be divided in two parts, 13002021 and 2120130, that added together give a palindrome (15122151).
The spelling of 130020212120130 in words is "one hundred thirty trillion, twenty billion, two hundred twelve million, one hundred twenty thousand, one hundred thirty".
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