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130020423213102 = 231737791019914357
BaseRepresentation
bin11101100100000010111101…
…001000111010000000101110
3122001100211102211220000020220
4131210002331020322000232
5114020223311320304402
61140310320254152210
736246444203151012
oct3544027510720056
9561324384800226
10130020423213102
1138479396307544
12126ba9b47b2666
135771b4783b176
14241704476c542
1510071e2560dbc
hex7640bd23a02e

130020423213102 has 256 divisors, whose sum is σ = 289551890350080. Its totient is φ = 38749860864000.

The previous prime is 130020423213101. The next prime is 130020423213103. The reversal of 130020423213102 is 201312324020031.

It is an interprime number because it is at equal distance from previous prime (130020423213101) and next prime (130020423213103).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130020423213101) by changing a digit.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 29841729108 + ... + 29841733464.

It is an arithmetic number, because the mean of its divisors is an integer number (1131062071680).

Almost surely, 2130020423213102 is an apocalyptic number.

130020423213102 is an abundant number, since it is smaller than the sum of its proper divisors (159531467136978).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130020423213102 is a wasteful number, since it uses less digits than its factorization.

130020423213102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5587.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 130020423213102 its reverse (201312324020031), we get a palindrome (331332747233133).

The spelling of 130020423213102 in words is "one hundred thirty trillion, twenty billion, four hundred twenty-three million, two hundred thirteen thousand, one hundred two".