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1300205969 is a prime number
BaseRepresentation
bin100110101111111…
…1001000110010001
310100121120022021122
41031133321012101
510130323042334
6333003532025
744135365646
oct11537710621
93317508248
101300205969
11607a28a97
1230352a015
131794aa95a
14c4975dcd
157923132e
hex4d7f9191

1300205969 has 2 divisors, whose sum is σ = 1300205970. Its totient is φ = 1300205968.

The previous prime is 1300205957. The next prime is 1300205971. The reversal of 1300205969 is 9695020031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1297440400 + 2765569 = 36020^2 + 1663^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300205969 - 228 = 1031770513 is a prime.

It is a super-2 number, since 2×13002059692 = 3381071123646457922, which contains 22 as substring.

Together with 1300205971, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1300205909) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650102984 + 650102985.

It is an arithmetic number, because the mean of its divisors is an integer number (650102985).

Almost surely, 21300205969 is an apocalyptic number.

It is an amenable number.

1300205969 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300205969 is an equidigital number, since it uses as much as digits as its factorization.

1300205969 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14580, while the sum is 35.

The square root of 1300205969 is about 36058.3689176313. The cubic root of 1300205969 is about 1091.4505192739.

The spelling of 1300205969 in words is "one billion, three hundred million, two hundred five thousand, nine hundred sixty-nine".