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1300210020121 is a prime number
BaseRepresentation
bin10010111010111010100…
…011100110111100011001
311121022001212112120200011
4102322322203212330121
5132300312231120441
62433150325041521
7162636262551055
oct22727243467431
94538055476604
101300210020121
11461463729441
1218bba58562a1
13957bc77c4bc
1446d05418c65
1523c4c5ad581
hex12eba8e6f19

1300210020121 has 2 divisors, whose sum is σ = 1300210020122. Its totient is φ = 1300210020120.

The previous prime is 1300210020077. The next prime is 1300210020157. The reversal of 1300210020121 is 1210200120031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1071247770121 + 228962250000 = 1035011^2 + 478500^2 .

It is a cyclic number.

It is not a de Polignac number, because 1300210020121 - 235 = 1265850281753 is a prime.

It is not a weakly prime, because it can be changed into another prime (1300210020521) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650105010060 + 650105010061.

It is an arithmetic number, because the mean of its divisors is an integer number (650105010061).

Almost surely, 21300210020121 is an apocalyptic number.

It is an amenable number.

1300210020121 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300210020121 is an equidigital number, since it uses as much as digits as its factorization.

1300210020121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 1300210020121 its reverse (1210200120031), we get a palindrome (2510410140152).

The spelling of 1300210020121 in words is "one trillion, three hundred billion, two hundred ten million, twenty thousand, one hundred twenty-one".