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130021021022 = 265010510511
BaseRepresentation
bin111100100010111011…
…0110101010101011110
3110102121101111020001012
41321011312311111132
54112240340133042
6135421505415222
712252020305064
oct1710566652536
9412541436035
10130021021022
1150161527582
122124793a512
13c3513548c9
1464161bc034
1535aeb16e82
hex1e45db555e

130021021022 has 4 divisors (see below), whose sum is σ = 195031531536. Its totient is φ = 65010510510.

The previous prime is 130021021019. The next prime is 130021021073. The reversal of 130021021022 is 220120120031.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 220120120031 = 731445731433.

It is a junction number, because it is equal to n+sod(n) for n = 130021020988 and 130021021006.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 32505255254 + ... + 32505255257.

It is an arithmetic number, because the mean of its divisors is an integer number (48757882884).

Almost surely, 2130021021022 is an apocalyptic number.

130021021022 is a deficient number, since it is larger than the sum of its proper divisors (65010510514).

130021021022 is an equidigital number, since it uses as much as digits as its factorization.

130021021022 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 65010510513.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 130021021022 its reverse (220120120031), we get a palindrome (350141141053).

Subtracting 130021021022 from its reverse (220120120031), we obtain a palindrome (90099099009).

The spelling of 130021021022 in words is "one hundred thirty billion, twenty-one million, twenty-one thousand, twenty-two".

Divisors: 1 2 65010510511 130021021022