Base | Representation |
---|---|
bin | 10010111010111010101… |
… | …100110110011110111101 |
3 | 11121022002001002200022222 |
4 | 102322322230312132331 |
5 | 132300313341134234 |
6 | 2433150453015125 |
7 | 162636322262051 |
oct | 22727254663675 |
9 | 4538061080288 |
10 | 1300212443069 |
11 | 461465033881 |
12 | 18bba66244a5 |
13 | 957c011a2b7 |
14 | 46d05889c61 |
15 | 23c4c8db42e |
hex | 12ebab367bd |
1300212443069 has 2 divisors, whose sum is σ = 1300212443070. Its totient is φ = 1300212443068.
The previous prime is 1300212443029. The next prime is 1300212443107. The reversal of 1300212443069 is 9603442120031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1102107334969 + 198105108100 = 1049813^2 + 445090^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1300212443069 is a prime.
It is a super-2 number, since 2×13002124430692 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1300212443029) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650106221534 + 650106221535.
It is an arithmetic number, because the mean of its divisors is an integer number (650106221535).
Almost surely, 21300212443069 is an apocalyptic number.
It is an amenable number.
1300212443069 is a deficient number, since it is larger than the sum of its proper divisors (1).
1300212443069 is an equidigital number, since it uses as much as digits as its factorization.
1300212443069 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 31104, while the sum is 35.
The spelling of 1300212443069 in words is "one trillion, three hundred billion, two hundred twelve million, four hundred forty-three thousand, sixty-nine".
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