Base | Representation |
---|---|
bin | 10010111010111010101… |
… | …100110110011111011110 |
3 | 11121022002001002200101012 |
4 | 102322322230312133132 |
5 | 132300313341134402 |
6 | 2433150453015222 |
7 | 162636322262126 |
oct | 22727254663736 |
9 | 4538061080335 |
10 | 1300212443102 |
11 | 461465033901 |
12 | 18bba6624512 |
13 | 957c011a311 |
14 | 46d05889c86 |
15 | 23c4c8db452 |
hex | 12ebab367de |
1300212443102 has 4 divisors (see below), whose sum is σ = 1950318664656. Its totient is φ = 650106221550.
The previous prime is 1300212443069. The next prime is 1300212443107. The reversal of 1300212443102 is 2013442120031.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1300212443107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 325053110774 + ... + 325053110777.
It is an arithmetic number, because the mean of its divisors is an integer number (487579666164).
Almost surely, 21300212443102 is an apocalyptic number.
1300212443102 is a deficient number, since it is larger than the sum of its proper divisors (650106221554).
1300212443102 is an equidigital number, since it uses as much as digits as its factorization.
1300212443102 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 650106221553.
The product of its (nonzero) digits is 1152, while the sum is 23.
Adding to 1300212443102 its reverse (2013442120031), we get a palindrome (3313654563133).
The spelling of 1300212443102 in words is "one trillion, three hundred billion, two hundred twelve million, four hundred forty-three thousand, one hundred two".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •