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130021330000 = 2454371272767
BaseRepresentation
bin111100100010111100…
…0000000110001010000
3110102121102001220212211
41321011320000301100
54112240430030000
6135421520201504
712252023032642
oct1710570006120
9412542056784
10130021330000
1150161718731
1221247a69294
13c351432433
14641625c892
1535aeb787ba
hex1e45e00c50

130021330000 has 200 divisors, whose sum is σ = 325966057472. Its totient is φ = 50186304000.

The previous prime is 130021329941. The next prime is 130021330003. The reversal of 130021330000 is 33120031.

It is a tau number, because it is divible by the number of its divisors (200).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130021330003) by changing a digit.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 46988617 + ... + 46991383.

Almost surely, 2130021330000 is an apocalyptic number.

130021330000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130021330000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (162983028736).

130021330000 is an abundant number, since it is smaller than the sum of its proper divisors (195944727472).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130021330000 is a wasteful number, since it uses less digits than its factorization.

130021330000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2959 (or 2938 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 13.

Adding to 130021330000 its reverse (33120031), we get a palindrome (130054450031).

The spelling of 130021330000 in words is "one hundred thirty billion, twenty-one million, three hundred thirty thousand".