13002201112139 has 2 divisors, whose sum is σ = 13002201112140. Its totient is φ = 13002201112138.

The previous prime is 13002201112133. The next prime is 13002201112141. The reversal of 13002201112139 is 93121110220031.

It is a strong prime.

It is an emirp because it is prime and its reverse (93121110220031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13002201112139 is a prime.

Together with 13002201112141, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13002201112133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6501100556069 + 6501100556070.

It is an arithmetic number, because the mean of its divisors is an integer number (6501100556070).

Almost surely, 2^{13002201112139} is an apocalyptic number.

13002201112139 is a deficient number, since it is larger than the sum of its proper divisors (1).

13002201112139 is an equidigital number, since it uses as much as digits as its factorization.

13002201112139 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 26.

The spelling of 13002201112139 in words is "thirteen trillion, two billion, two hundred one million, one hundred twelve thousand, one hundred thirty-nine".