130022015201143 has 4 divisors (see below), whose sum is σ = 140023708678168. Its totient is φ = 120020321724120.

The previous prime is 130022015201033. The next prime is 130022015201159. The reversal of 130022015201143 is 341102510220031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 130022015201143 - 2¹⁷ = 130022015070071 is a prime.

It is a super-2 number, since 2×130022015201143² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130022015202143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5000846738493 + ... + 5000846738518.

It is an arithmetic number, because the mean of its divisors is an integer number (35005927169542).

Almost surely, 2^{130022015201143} is an apocalyptic number.

130022015201143 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

130022015201143 is a deficient number, since it is larger than the sum of its proper divisors (10001693477025).

130022015201143 is a wasteful number, since it uses less digits than its factorization.

130022015201143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10001693477024.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 130022015201143 its reverse (341102510220031), we get a palindrome (471124525421174).

The spelling of 130022015201143 in words is "one hundred thirty trillion, twenty-two billion, fifteen million, two hundred one thousand, one hundred forty-three".