Base | Representation |
---|---|
bin | 11101100100000100011100… |
… | …000001110111001101011111 |
3 | 122001100222112210111102122222 |
4 | 131210010130001313031133 |
5 | 114020240041342432033 |
6 | 1140311142244055555 |
7 | 36246531513634331 |
oct | 3544043401671537 |
9 | 561328483442588 |
10 | 130022015202143 |
11 | 3847a032a07469 |
12 | 126bb1799945bb |
13 | 577203c5ca80c |
14 | 2417155d79451 |
15 | 10072871cb598 |
hex | 76411c07735f |
130022015202143 has 2 divisors, whose sum is σ = 130022015202144. Its totient is φ = 130022015202142.
The previous prime is 130022015202137. The next prime is 130022015202161. The reversal of 130022015202143 is 341202510220031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130022015202143 - 28 = 130022015201887 is a prime.
It is a Sophie Germain prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130022015202943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65011007601071 + 65011007601072.
It is an arithmetic number, because the mean of its divisors is an integer number (65011007601072).
Almost surely, 2130022015202143 is an apocalyptic number.
130022015202143 is a deficient number, since it is larger than the sum of its proper divisors (1).
130022015202143 is an equidigital number, since it uses as much as digits as its factorization.
130022015202143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2880, while the sum is 26.
Adding to 130022015202143 its reverse (341202510220031), we get a palindrome (471224525422174).
The spelling of 130022015202143 in words is "one hundred thirty trillion, twenty-two billion, fifteen million, two hundred two thousand, one hundred forty-three".
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