Base | Representation |
---|---|
bin | 1011110100110100111110… |
… | …1010010111011010111010 |
3 | 1201000222221211220200102020 |
4 | 2331031033222113122322 |
5 | 3201012002320323114 |
6 | 43353043540015310 |
7 | 2511243461546352 |
oct | 275151752273272 |
9 | 51028854820366 |
10 | 13002202511034 |
11 | 4163226394950 |
12 | 155bab7391536 |
13 | 734144088999 |
14 | 32d44a757b62 |
15 | 17833cbecaa9 |
hex | bd34fa976ba |
13002202511034 has 16 divisors (see below), whose sum is σ = 28368441842400. Its totient is φ = 3940061366960.
The previous prime is 13002202510963. The next prime is 13002202511041. The reversal of 13002202511034 is 43011520220031.
It is a junction number, because it is equal to n+sod(n) for n = 13002202510995 and 13002202511013.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 98501534109 + ... + 98501534240.
It is an arithmetic number, because the mean of its divisors is an integer number (1773027615150).
Almost surely, 213002202511034 is an apocalyptic number.
13002202511034 is an abundant number, since it is smaller than the sum of its proper divisors (15366239331366).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13002202511034 is a wasteful number, since it uses less digits than its factorization.
13002202511034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 197003068365.
The product of its (nonzero) digits is 1440, while the sum is 24.
Adding to 13002202511034 its reverse (43011520220031), we get a palindrome (56013722731065).
The spelling of 13002202511034 in words is "thirteen trillion, two billion, two hundred two million, five hundred eleven thousand, thirty-four".
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