Base | Representation |
---|---|
bin | 10010111010111011010… |
… | …101100111111001011111 |
3 | 11121022002210012200201211 |
4 | 102322323111213321133 |
5 | 132300324110144411 |
6 | 2433151514045251 |
7 | 162636512155633 |
oct | 22727325477137 |
9 | 4538083180654 |
10 | 1300223131231 |
11 | 461470073a72 |
12 | 18bbaa119827 |
13 | 957c23c015b |
14 | 46d0706cdc3 |
15 | 23c4d7ed221 |
hex | 12ebb567e5f |
1300223131231 has 2 divisors, whose sum is σ = 1300223131232. Its totient is φ = 1300223131230.
The previous prime is 1300223131211. The next prime is 1300223131267. The reversal of 1300223131231 is 1321313220031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1300223131231 - 213 = 1300223123039 is a prime.
It is a super-2 number, since 2×13002231312312 (a number of 25 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1300223131211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650111565615 + 650111565616.
It is an arithmetic number, because the mean of its divisors is an integer number (650111565616).
Almost surely, 21300223131231 is an apocalyptic number.
1300223131231 is a deficient number, since it is larger than the sum of its proper divisors (1).
1300223131231 is an equidigital number, since it uses as much as digits as its factorization.
1300223131231 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 1300223131231 its reverse (1321313220031), we get a palindrome (2621536351262).
The spelling of 1300223131231 in words is "one trillion, three hundred billion, two hundred twenty-three million, one hundred thirty-one thousand, two hundred thirty-one".
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