Search a number
-
+
130022414057 is a prime number
BaseRepresentation
bin111100100010111110…
…0001001011011101001
3110102121111002222221002
41321011330021123221
54112241214222212
6135421555324345
712252035166314
oct1710574113351
9412544088832
10130022414057
1150162299148
12212482b06b5
13c3517219a3
14641646197b
1535aecdeac2
hex1e45f096e9

130022414057 has 2 divisors, whose sum is σ = 130022414058. Its totient is φ = 130022414056.

The previous prime is 130022414029. The next prime is 130022414177. The reversal of 130022414057 is 750414220031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 88619931481 + 41402482576 = 297691^2 + 203476^2 .

It is a cyclic number.

It is not a de Polignac number, because 130022414057 - 212 = 130022409961 is a prime.

It is not a weakly prime, because it can be changed into another prime (130022414957) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65011207028 + 65011207029.

It is an arithmetic number, because the mean of its divisors is an integer number (65011207029).

Almost surely, 2130022414057 is an apocalyptic number.

It is an amenable number.

130022414057 is a deficient number, since it is larger than the sum of its proper divisors (1).

130022414057 is an equidigital number, since it uses as much as digits as its factorization.

130022414057 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6720, while the sum is 29.

Adding to 130022414057 its reverse (750414220031), we get a palindrome (880436634088).

The spelling of 130022414057 in words is "one hundred thirty billion, twenty-two million, four hundred fourteen thousand, fifty-seven".