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130022414177 is a prime number
BaseRepresentation
bin111100100010111110…
…0001001011101100001
3110102121111010000002112
41321011330021131201
54112241214223202
6135421555325105
712252035166545
oct1710574113541
9412544100075
10130022414177
1150162299247
12212482b0795
13c351721a66
146416461a25
1535aecdeb52
hex1e45f09761

130022414177 has 2 divisors, whose sum is σ = 130022414178. Its totient is φ = 130022414176.

The previous prime is 130022414057. The next prime is 130022414209. The reversal of 130022414177 is 771414220031.

It is an a-pointer prime, because the next prime (130022414209) can be obtained adding 130022414177 to its sum of digits (32).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 75209771536 + 54812642641 = 274244^2 + 234121^2 .

It is a cyclic number.

It is not a de Polignac number, because 130022414177 - 214 = 130022397793 is a prime.

It is not a weakly prime, because it can be changed into another prime (130022464177) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65011207088 + 65011207089.

It is an arithmetic number, because the mean of its divisors is an integer number (65011207089).

Almost surely, 2130022414177 is an apocalyptic number.

It is an amenable number.

130022414177 is a deficient number, since it is larger than the sum of its proper divisors (1).

130022414177 is an equidigital number, since it uses as much as digits as its factorization.

130022414177 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9408, while the sum is 32.

The spelling of 130022414177 in words is "one hundred thirty billion, twenty-two million, four hundred fourteen thousand, one hundred seventy-seven".