Base | Representation |
---|---|
bin | 111100100010111111… |
… | …0011011001100011111 |
3 | 110102121112020022220220 |
4 | 1321011332123030133 |
5 | 4112241342323403 |
6 | 135422020212423 |
7 | 12252043234056 |
oct | 1710576331437 |
9 | 412545208826 |
10 | 130023011103 |
11 | 50162666777 |
12 | 2124853a113 |
13 | c3518a067b |
14 | 641657939d |
15 | 35aedab953 |
hex | 1e45f9b31f |
130023011103 has 32 divisors (see below), whose sum is σ = 179916249600. Its totient is φ = 83425507200.
The previous prime is 130023011033. The next prime is 130023011117. The reversal of 130023011103 is 301110320031.
It is not a de Polignac number, because 130023011103 - 28 = 130023010847 is a prime.
It is a super-2 number, since 2×1300230111032 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130023011143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 47959918 + ... + 47962628.
It is an arithmetic number, because the mean of its divisors is an integer number (5622382800).
Almost surely, 2130023011103 is an apocalyptic number.
130023011103 is a deficient number, since it is larger than the sum of its proper divisors (49893238497).
130023011103 is a wasteful number, since it uses less digits than its factorization.
130023011103 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4303.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 130023011103 its reverse (301110320031), we get a palindrome (431133331134).
The spelling of 130023011103 in words is "one hundred thirty billion, twenty-three million, eleven thousand, one hundred three".
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