Base | Representation |
---|---|
bin | 111100100010111111… |
… | …0011011001101000111 |
3 | 110102121112020022222101 |
4 | 1321011332123031013 |
5 | 4112241342324033 |
6 | 135422020212531 |
7 | 12252043234144 |
oct | 1710576331507 |
9 | 412545208871 |
10 | 130023011143 |
11 | 50162666803 |
12 | 2124853a147 |
13 | c3518a06ac |
14 | 64165793cb |
15 | 35aedab97d |
hex | 1e45f9b347 |
130023011143 has 2 divisors, whose sum is σ = 130023011144. Its totient is φ = 130023011142.
The previous prime is 130023011117. The next prime is 130023011213. The reversal of 130023011143 is 341110320031.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130023011143 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 130023011143.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130023011743) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65011505571 + 65011505572.
It is an arithmetic number, because the mean of its divisors is an integer number (65011505572).
Almost surely, 2130023011143 is an apocalyptic number.
130023011143 is a deficient number, since it is larger than the sum of its proper divisors (1).
130023011143 is an equidigital number, since it uses as much as digits as its factorization.
130023011143 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 130023011143 its reverse (341110320031), we get a palindrome (471133331174).
The spelling of 130023011143 in words is "one hundred thirty billion, twenty-three million, eleven thousand, one hundred forty-three".
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