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13002301110300 = 223522954110192711
BaseRepresentation
bin1011110100110101010110…
…0010011111100000011100
31201001000012201110001011220
42331031111202133200130
53201012203041012200
643353101421213340
72511246066615645
oct275152542374034
951030181401156
1013002301110300
114163277009a47
12155bb24401250
1373415b62ba48
1432d4598a26cc
151783466c74a0
hexbd35589f81c

13002301110300 has 288 divisors, whose sum is σ = 39041826163200. Its totient is φ = 3337020288000.

The previous prime is 13002301110191. The next prime is 13002301110361. The reversal of 13002301110300 is 301110320031.

It is a super-2 number, since 2×130023011103002 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 13002301110300.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 4796125945 + ... + 4796128655.

It is an arithmetic number, because the mean of its divisors is an integer number (135561896400).

Almost surely, 213002301110300 is an apocalyptic number.

13002301110300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13002301110300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19520913081600).

13002301110300 is an abundant number, since it is smaller than the sum of its proper divisors (26039525052900).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13002301110300 is a wasteful number, since it uses less digits than its factorization.

13002301110300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4317 (or 4310 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 13002301110300 its reverse (301110320031), we get a palindrome (13303411430331).

The spelling of 13002301110300 in words is "thirteen trillion, two billion, three hundred one million, one hundred ten thousand, three hundred".