Base | Representation |
---|---|
bin | 1011110100110101010110… |
… | …0010011111011110101111 |
3 | 1201001000012201110001000212 |
4 | 2331031111202133132233 |
5 | 3201012203041011231 |
6 | 43353101421213035 |
7 | 2511246066615431 |
oct | 275152542373657 |
9 | 51030181401025 |
10 | 13002301110191 |
11 | 4163277009958 |
12 | 155bb2440117b |
13 | 73415b62b993 |
14 | 32d4598a2651 |
15 | 1783466c742b |
hex | bd35589f7af |
13002301110191 has 2 divisors, whose sum is σ = 13002301110192. Its totient is φ = 13002301110190.
The previous prime is 13002301110187. The next prime is 13002301110361. The reversal of 13002301110191 is 19101110320031.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13002301110191 - 22 = 13002301110187 is a prime.
It is a super-2 number, since 2×130023011101912 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13002301110151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6501150555095 + 6501150555096.
It is an arithmetic number, because the mean of its divisors is an integer number (6501150555096).
Almost surely, 213002301110191 is an apocalyptic number.
13002301110191 is a deficient number, since it is larger than the sum of its proper divisors (1).
13002301110191 is an equidigital number, since it uses as much as digits as its factorization.
13002301110191 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 23.
The spelling of 13002301110191 in words is "thirteen trillion, two billion, three hundred one million, one hundred ten thousand, one hundred ninety-one".
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