Base | Representation |
---|---|
bin | 11101100100000101011100… |
… | …110000001111010001001101 |
3 | 122001101002100110210211001002 |
4 | 131210011130300033101031 |
5 | 114020244302340214013 |
6 | 1140311442114430045 |
7 | 36246600440630522 |
oct | 3544053460172115 |
9 | 561332313724032 |
10 | 130023101101133 |
11 | 3847a53a970449 |
12 | 126bb421592325 |
13 | 57721835820b6 |
14 | 241721a287149 |
15 | 10072ec6c9358 |
hex | 76415cc0f44d |
130023101101133 has 2 divisors, whose sum is σ = 130023101101134. Its totient is φ = 130023101101132.
The previous prime is 130023101101097. The next prime is 130023101101151. The reversal of 130023101101133 is 331101101320031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 114488758803364 + 15534342297769 = 10699942^2 + 3941363^2 .
It is a cyclic number.
It is not a de Polignac number, because 130023101101133 - 28 = 130023101100877 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130023101151133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65011550550566 + 65011550550567.
It is an arithmetic number, because the mean of its divisors is an integer number (65011550550567).
Almost surely, 2130023101101133 is an apocalyptic number.
It is an amenable number.
130023101101133 is a deficient number, since it is larger than the sum of its proper divisors (1).
130023101101133 is an equidigital number, since it uses as much as digits as its factorization.
130023101101133 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162, while the sum is 20.
Adding to 130023101101133 its reverse (331101101320031), we get a palindrome (461124202421164).
The spelling of 130023101101133 in words is "one hundred thirty trillion, twenty-three billion, one hundred one million, one hundred one thousand, one hundred thirty-three".
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