Base | Representation |
---|---|
bin | 1011110100110101101101… |
… | …1100111111110101100001 |
3 | 1201001000110122011002100101 |
4 | 2331031123130333311201 |
5 | 3201012403441130103 |
6 | 43353115324022401 |
7 | 2511251413163260 |
oct | 275153334776541 |
9 | 51030418132311 |
10 | 13002400333153 |
11 | 416331801a600 |
12 | 155bb51691a01 |
13 | 73417605c8aa |
14 | 32d468b305d7 |
15 | 178350276a1d |
hex | bd35b73fd61 |
13002400333153 has 24 divisors (see below), whose sum is σ = 16681117130496. Its totient is φ = 9916171541760.
The previous prime is 13002400333147. The next prime is 13002400333187. The reversal of 13002400333153 is 35133300420031.
It is not a de Polignac number, because 13002400333153 - 25 = 13002400333121 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13002400333193) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 163270000 + ... + 163349617.
It is an arithmetic number, because the mean of its divisors is an integer number (695046547104).
Almost surely, 213002400333153 is an apocalyptic number.
It is an amenable number.
13002400333153 is a deficient number, since it is larger than the sum of its proper divisors (3678716797343).
13002400333153 is a wasteful number, since it uses less digits than its factorization.
13002400333153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 326619693 (or 326619682 counting only the distinct ones).
The product of its (nonzero) digits is 9720, while the sum is 28.
Adding to 13002400333153 its reverse (35133300420031), we get a palindrome (48135700753184).
The spelling of 13002400333153 in words is "thirteen trillion, two billion, four hundred million, three hundred thirty-three thousand, one hundred fifty-three".
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