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130024241420023 is a prime number
BaseRepresentation
bin11101100100000110100000…
…101110001101011011110111
3122001101012021221112000111001
4131210012200232031123313
5114020304121300420043
61140312151211424131
736246640625320426
oct3544064056153367
9561335257460431
10130024241420023
113847aa75613955
12126bb69b455047
1357723058ab7c2
1424172c78bd2bd
15100736787674d
hex7641a0b8d6f7

130024241420023 has 2 divisors, whose sum is σ = 130024241420024. Its totient is φ = 130024241420022.

The previous prime is 130024241419991. The next prime is 130024241420111. The reversal of 130024241420023 is 320024142420031.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 130024241420023 - 25 = 130024241419991 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130024241419973 and 130024241420000.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130024248420023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65012120710011 + 65012120710012.

It is an arithmetic number, because the mean of its divisors is an integer number (65012120710012).

Almost surely, 2130024241420023 is an apocalyptic number.

130024241420023 is a deficient number, since it is larger than the sum of its proper divisors (1).

130024241420023 is an equidigital number, since it uses as much as digits as its factorization.

130024241420023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9216, while the sum is 28.

Adding to 130024241420023 its reverse (320024142420031), we get a palindrome (450048383840054).

The spelling of 130024241420023 in words is "one hundred thirty trillion, twenty-four billion, two hundred forty-one million, four hundred twenty thousand, twenty-three".