Base | Representation |
---|---|
bin | 11101100100000110100000… |
… | …101110001101011011110111 |
3 | 122001101012021221112000111001 |
4 | 131210012200232031123313 |
5 | 114020304121300420043 |
6 | 1140312151211424131 |
7 | 36246640625320426 |
oct | 3544064056153367 |
9 | 561335257460431 |
10 | 130024241420023 |
11 | 3847aa75613955 |
12 | 126bb69b455047 |
13 | 57723058ab7c2 |
14 | 24172c78bd2bd |
15 | 100736787674d |
hex | 7641a0b8d6f7 |
130024241420023 has 2 divisors, whose sum is σ = 130024241420024. Its totient is φ = 130024241420022.
The previous prime is 130024241419991. The next prime is 130024241420111. The reversal of 130024241420023 is 320024142420031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130024241420023 - 25 = 130024241419991 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130024241419973 and 130024241420000.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130024248420023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65012120710011 + 65012120710012.
It is an arithmetic number, because the mean of its divisors is an integer number (65012120710012).
Almost surely, 2130024241420023 is an apocalyptic number.
130024241420023 is a deficient number, since it is larger than the sum of its proper divisors (1).
130024241420023 is an equidigital number, since it uses as much as digits as its factorization.
130024241420023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 9216, while the sum is 28.
Adding to 130024241420023 its reverse (320024142420031), we get a palindrome (450048383840054).
The spelling of 130024241420023 in words is "one hundred thirty trillion, twenty-four billion, two hundred forty-one million, four hundred twenty thousand, twenty-three".
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