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1300244137 is a prime number
BaseRepresentation
bin100110110000000…
…0010011010101001
310100121122020122021
41031200002122221
510130330303022
6333004424441
744135615143
oct11540023251
93317566567
101300244137
11607a54735
12303548121
131794c213a
14c4985c93
157923c7c7
hex4d8026a9

1300244137 has 2 divisors, whose sum is σ = 1300244138. Its totient is φ = 1300244136.

The previous prime is 1300244123. The next prime is 1300244147. The reversal of 1300244137 is 7314420031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1296288016 + 3956121 = 36004^2 + 1989^2 .

It is an emirp because it is prime and its reverse (7314420031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1300244137 - 211 = 1300242089 is a prime.

It is not a weakly prime, because it can be changed into another prime (1300244147) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650122068 + 650122069.

It is an arithmetic number, because the mean of its divisors is an integer number (650122069).

Almost surely, 21300244137 is an apocalyptic number.

It is an amenable number.

1300244137 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300244137 is an equidigital number, since it uses as much as digits as its factorization.

1300244137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016, while the sum is 25.

The square root of 1300244137 is about 36058.8981667494. The cubic root of 1300244137 is about 1091.4611991397.

Adding to 1300244137 its reverse (7314420031), we get a palindrome (8614664168).

The spelling of 1300244137 in words is "one billion, three hundred million, two hundred forty-four thousand, one hundred thirty-seven".