Base | Representation |
---|---|
bin | 11101100100000111000011… |
… | …110100101111000111001101 |
3 | 122001101020210222122220202012 |
4 | 131210013003310233013031 |
5 | 114020311323031132024 |
6 | 1140312325450111005 |
7 | 36246661336103135 |
oct | 3544070364570715 |
9 | 561336728586665 |
10 | 130024830333389 |
11 | 38480247a8a212 |
12 | 126bb82471b465 |
13 | 577239a8c5054 |
14 | 2417341bbbac5 |
15 | 100739e40450e |
hex | 7641c3d2f1cd |
130024830333389 has 2 divisors, whose sum is σ = 130024830333390. Its totient is φ = 130024830333388.
The previous prime is 130024830333329. The next prime is 130024830333401. The reversal of 130024830333389 is 983333038420031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 88331012777764 + 41693817555625 = 9398458^2 + 6457075^2 .
It is a cyclic number.
It is not a de Polignac number, because 130024830333389 - 220 = 130024829284813 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130024830333329) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65012415166694 + 65012415166695.
It is an arithmetic number, because the mean of its divisors is an integer number (65012415166695).
Almost surely, 2130024830333389 is an apocalyptic number.
It is an amenable number.
130024830333389 is a deficient number, since it is larger than the sum of its proper divisors (1).
130024830333389 is an equidigital number, since it uses as much as digits as its factorization.
130024830333389 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3359232, while the sum is 50.
The spelling of 130024830333389 in words is "one hundred thirty trillion, twenty-four billion, eight hundred thirty million, three hundred thirty-three thousand, three hundred eighty-nine".
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