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130025025131 is a prime number
BaseRepresentation
bin111100100011000011…
…0000110111001101011
3110102121200000122122112
41321012012012321223
54112242401301011
6135422131312535
712252066322631
oct1710606067153
9412550018575
10130025025131
1150163811961
122124914b74b
13c3521272c1
146416941351
1535b015858b
hex1e46186e6b

130025025131 has 2 divisors, whose sum is σ = 130025025132. Its totient is φ = 130025025130.

The previous prime is 130025025127. The next prime is 130025025191. The reversal of 130025025131 is 131520520031.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 130025025131 - 22 = 130025025127 is a prime.

It is a super-2 number, since 2×1300250251312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130025025097 and 130025025106.

It is not a weakly prime, because it can be changed into another prime (130025025101) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65012512565 + 65012512566.

It is an arithmetic number, because the mean of its divisors is an integer number (65012512566).

Almost surely, 2130025025131 is an apocalyptic number.

130025025131 is a deficient number, since it is larger than the sum of its proper divisors (1).

130025025131 is an equidigital number, since it uses as much as digits as its factorization.

130025025131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 900, while the sum is 23.

Adding to 130025025131 its reverse (131520520031), we get a palindrome (261545545162).

The spelling of 130025025131 in words is "one hundred thirty billion, twenty-five million, twenty-five thousand, one hundred thirty-one".