Base | Representation |
---|---|
bin | 111100100011000011… |
… | …1010010000100001101 |
3 | 110102121200121021222021 |
4 | 1321012013102010031 |
5 | 4112242441124010 |
6 | 135422142050141 |
7 | 12252102044341 |
oct | 1710607220415 |
9 | 412550537867 |
10 | 130025333005 |
11 | 50163a021a7 |
12 | 21249279951 |
13 | c352204489 |
14 | 64169c1621 |
15 | 35b01b98da |
hex | 1e461d210d |
130025333005 has 8 divisors (see below), whose sum is σ = 156585669624. Its totient is φ = 103650086400.
The previous prime is 130025332961. The next prime is 130025333021. The reversal of 130025333005 is 500333520031.
It is a happy number.
It can be written as a sum of positive squares in 4 ways, for example, as 14427372996 + 115597960009 = 120114^2 + 339997^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is a de Polignac number, because none of the positive numbers 2k-130025333005 is a prime.
It is a super-2 number, since 2×1300253330052 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 46270956 + ... + 46273765.
It is an arithmetic number, because the mean of its divisors is an integer number (19573208703).
Almost surely, 2130025333005 is an apocalyptic number.
It is an amenable number.
130025333005 is a deficient number, since it is larger than the sum of its proper divisors (26560336619).
130025333005 is an equidigital number, since it uses as much as digits as its factorization.
130025333005 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 92545007.
The product of its (nonzero) digits is 4050, while the sum is 25.
Adding to 130025333005 its reverse (500333520031), we get a palindrome (630358853036).
The spelling of 130025333005 in words is "one hundred thirty billion, twenty-five million, three hundred thirty-three thousand, five".
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