Base | Representation |
---|---|
bin | 1011110100110110010001… |
… | …1001111011000001010111 |
3 | 1201001000212002202110122011 |
4 | 2331031210121323001113 |
5 | 3201013210413200233 |
6 | 43353142251045051 |
7 | 2511255215600413 |
oct | 275154431730127 |
9 | 51030762673564 |
10 | 13002550521943 |
11 | 4163394880674 |
12 | 155bb93a40787 |
13 | 73419b1c66b8 |
14 | 32d480a67d43 |
15 | 17835d5420cd |
hex | bd36467b057 |
13002550521943 has 2 divisors, whose sum is σ = 13002550521944. Its totient is φ = 13002550521942.
The previous prime is 13002550521907. The next prime is 13002550521977. The reversal of 13002550521943 is 34912505520031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13002550521943 - 217 = 13002550390871 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13002550521896 and 13002550521905.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13002550522943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6501275260971 + 6501275260972.
It is an arithmetic number, because the mean of its divisors is an integer number (6501275260972).
Almost surely, 213002550521943 is an apocalyptic number.
13002550521943 is a deficient number, since it is larger than the sum of its proper divisors (1).
13002550521943 is an equidigital number, since it uses as much as digits as its factorization.
13002550521943 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 162000, while the sum is 40.
The spelling of 13002550521943 in words is "thirteen trillion, two billion, five hundred fifty million, five hundred twenty-one thousand, nine hundred forty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.080 sec. • engine limits •